b^2-5b+9=0

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Solution for b^2-5b+9=0 equation:


Simplifying
b2 + -5b + 9 = 0

Reorder the terms:
9 + -5b + b2 = 0

Solving
9 + -5b + b2 = 0

Solving for variable 'b'.

Begin completing the square.

Move the constant term to the right:

Add '-9' to each side of the equation.
9 + -5b + -9 + b2 = 0 + -9

Reorder the terms:
9 + -9 + -5b + b2 = 0 + -9

Combine like terms: 9 + -9 = 0
0 + -5b + b2 = 0 + -9
-5b + b2 = 0 + -9

Combine like terms: 0 + -9 = -9
-5b + b2 = -9

The b term is -5b.  Take half its coefficient (-2.5).
Square it (6.25) and add it to both sides.

Add '6.25' to each side of the equation.
-5b + 6.25 + b2 = -9 + 6.25

Reorder the terms:
6.25 + -5b + b2 = -9 + 6.25

Combine like terms: -9 + 6.25 = -2.75
6.25 + -5b + b2 = -2.75

Factor a perfect square on the left side:
(b + -2.5)(b + -2.5) = -2.75

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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